2v^2+4v+2=8

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Solution for 2v^2+4v+2=8 equation:


Simplifying
2v2 + 4v + 2 = 8

Reorder the terms:
2 + 4v + 2v2 = 8

Solving
2 + 4v + 2v2 = 8

Solving for variable 'v'.

Reorder the terms:
2 + -8 + 4v + 2v2 = 8 + -8

Combine like terms: 2 + -8 = -6
-6 + 4v + 2v2 = 8 + -8

Combine like terms: 8 + -8 = 0
-6 + 4v + 2v2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-3 + 2v + v2) = 0

Factor a trinomial.
2((-3 + -1v)(1 + -1v)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-3 + -1v)' equal to zero and attempt to solve: Simplifying -3 + -1v = 0 Solving -3 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1v = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1v = 0 + 3 -1v = 0 + 3 Combine like terms: 0 + 3 = 3 -1v = 3 Divide each side by '-1'. v = -3 Simplifying v = -3

Subproblem 2

Set the factor '(1 + -1v)' equal to zero and attempt to solve: Simplifying 1 + -1v = 0 Solving 1 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1v = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1v = 0 + -1 -1v = 0 + -1 Combine like terms: 0 + -1 = -1 -1v = -1 Divide each side by '-1'. v = 1 Simplifying v = 1

Solution

v = {-3, 1}

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